Bradley Beach 1929

Alekhine concedes only half a point at Bradley Beach
3–12 June 1929 · Bradley Beach, New Jersey, United States
Alekhine won with 8½/9

Alexander Alekhine won Bradley Beach 1929 with 8½ points from nine games. Ten players completed a forty-five-game single round robin, and the winner yielded only one half-point.

An 8½-out-of-9 finish

The direct historical crosstable records Alekhine first on 8½ points from nine games. The score is half a point short of the maximum in a ten-player single round robin.

Play at Bradley Beach ran from 3 through 12 June 1929.

All forty-five games

Every pairing is here, all forty-five games, so both Alekhine's result and the full standings come straight from the games.

Final standings

8½/9
Alekhine won with 8½/9
# Player Score Record Games
1 Alekhine, Alexander 8½/9 +8 -0 =1
2 Steiner, Lajos 7/9 +6 -1 =2
=3 Kupchik, Abraham 5½/9 +4 -2 =3
=3 Turover, Isador Samuel 5½/9 +4 -2 =3
5 Fox, Maurice 5/9 +4 -3 =2
6 Marshall, Frank James 4½/9 +3 -3 =3
7 Kevitz, Alexander 4/9 +3 -4 =2
8 Steiner, Herman 2½/9 +2 -6 =1
9 Cintron, Rafael L 2/9 +2 -7 =0
10 Bigelow, Horace Ransom ½/9 +0 -8 =1

Cross Table

Rank Player 12345678910
1 Alekhine, Alexander 1 ½ 1 1 1 1 1 1 1
2 Steiner, Lajos 0 1 ½ 1 ½ 1 1 1 1
3 Kupchik, Abraham ½ 0 ½ 1 ½ 1 0 1 1
4 Turover, Isador Samuel 0 ½ ½ ½ 1 0 1 1 1
5 Fox, Maurice 0 0 0 ½ ½ 1 1 1 1
6 Marshall, Frank James 0 ½ ½ 0 ½ 0 1 1 1
7 Kevitz, Alexander 0 0 0 1 0 1 ½ 1 ½
8 Steiner, Herman 0 0 1 0 0 0 ½ 0 1
9 Cintron, Rafael L 0 0 0 0 0 0 0 1 1
10 Bigelow, Horace Ransom 0 0 0 0 0 0 ½ 0 0

Each cell shows the row player's recorded results against the column player. ● = same player.